if Sin Q = 1/3 then the value of (9cot square Q + 9) is

(a) 1 (b) 81 (c) 9 (d) 1/81

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if Sin Q = 1/3 then the value of (9cot square Q + 9) is
(a) 1 (b) 81 (c) 9 (d) 1/81

Anuradha Sharma · Accepted Answer

sinQ=13so cosec Q=3Now 9cot2Q+9=9×cosec2Q-1+9Now putting the value of cosec Q we get, =99-1+9=81

if Sin Q = 1/3 then the value of (9cot square Q + 9) is (a) 1 (b) 81 (c) 9 (d) 1/81