If sinA=1/2, show that 3cosA-4cos3A=0
since sinA=1/2;therefore hypotenuse = 2 and opposite side of <A=1...;therfore 3cosA=3 x root3/2;which is equal to 4cos3A...therfore 3cosA-4cos3A=0
If sinA=1/2, show that 3cosA-4cos3A=0
since sinA=1/2;therefore hypotenuse = 2 and opposite side of <A=1...;therfore 3cosA=3 x root3/2;which is equal to 4cos3A...therfore 3cosA-4cos3A=0