If sinA=12/13, 0<A<90, find the value of sin^2A- cos^2A/2sinAcosA x 1/tan^2A Share with your friends Share 3 Lovina Kansal answered this Dear student Given: sinA=1213=PHBy Pythagoras theorem,B=H2-P2=132-122=169-144=5So, cosA=BH=513tanA=PB=125Thus,sin2A-cos2A2sinA cosA×1tan2A=12132-513221213513×11252=144169-25169120169×25144=119120×25144=11924×5144=5953456 Regards 3 View Full Answer
