If SinQ =3/5 and Q is an acute angle Find : (1) CosQ ,(2) tanQ

Ravi I Have not studied the term sin theta cos theta or tangent theta just I have heard about them.
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IN YOUR QUESTION ITS THITA ​θ NOT Q OK 
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IN YOUR QUESTION ITS THITA ​θ NOT Q OK 
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4/5 and 3/4
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Question no 37, 38, 39, 40, 41

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a) sin2Q+cos2Q=1
(3/5)2+cos2Q=1
cos2Q=1-9/25
cos Q=square root of (16/25)=4/5
b) tan Q=sin Q/cos Q
=(3/5)/(4/5)
=3/4
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If sinq =3/5 and q is an acute angle find tanq
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