If tan theta =2 evaluate tan?theta -cosec theta +sin theta sec theta

Dear student,

Assuming to evaluate is tan2θ-cosecθ+sinθsecθGiven: tanθ=2PerpendicularBase=PB=21In rt  ABC

Pythagoras theoremH2=P2+B2H2=22+12H2=4+1H2=5H=±5H=5                    --[neglectin -ve value]To find tan2θ-cosecθ+sinθsecθ=PB2-HP+PHHB=212-52+25×51=4-52+2=8-5+42=12-52

Regards

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