If tan2X=2tan2Y+1 , then find the value of cos2X+sin2Y?

tan2x=2tan2y+1Adding 1 both sidestan2x+1=2tan2y+1+1sec2x=2(tan2y+1)sec2x=2sec2ycos2x=cos2y/22cos2x=cos2ySubtracting 1 from both sides2cos2x-1=cos2y-1cos2x=-(1-cos2y)=-sin2ySocos 2x+sin2y=(-sin2y)+sin2y=0                                 Answer

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