If tanx =1/2 and tany= 1/3 find x+y

tan(X+Y)= tanX+tanY/1-tanXtanY
​              
1/2+1/3/1-1/2.1/3=1
  • 10
tanx=1/2,tany=1/3 so to find tan(x+y) we would use the formula tanx+tany/1-tanxtany 
 
by putting the given value 
1/2+1/3/1-1/2x1/3
so by lcm we get
3+2\6 numerator ....1
denominator 6-1\6 ......2
by solving 1 and 2 we get 5/5=1 
so the answer is 1

​                                                                                                        
  • 4
This is answer

  • 1
Place a call to
  • -2
What are you looking for?