If the 5th term of an A.P. is 1/10 and the 10th term is 1/5 then find the 50th term of an A.P.

 a+(5-1)d=1/10

 a + (10-1)d = 1/5

so, (4-9)d=1/10-1/5

or, 5d=1/10

or,d=1/50

so, a = 1/5-9/50 = 1/50

s, 50th term = 1/50+(50-1)x1/50 = 1/50+49/50 = 1 (answer)

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