If the density of copper is 8.94 g/cm^3 the number of Faradays required to plate an area (10cm 10cm) of thickness of 10^-2cm using CuSO4 solution as electrolyte is

Dear Student,Amount of copper deposited =Mass of copper depositedMolar mass of copperAmount of copper deposited =Density ×Volume  of copper depositedMolar mass of copperAmount of copper deposited =8.9410×10×1063 = 0.1422 electrons are required to convert Cu2+ to CuThe number of faradays passed or electricity passed = n no. of electron×F ×Amount of copper depositedThe number of faradays passed or electricity passed =2×96500 × 0.142The number of faradays passed or electricity passed =27406 C

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