If the difference between the corresponding roots of x^2 + ax +b=0 and x^2 +bx +a =0 is same and a is not equal to b, then A)a+b+4=0 B)a+b-4=0 C)a-b-4=0 D)a-b+4=0 Please don't give similar links ! Share with your friends Share 15 Lovina Kansal answered this Dear student Let α,β and γ,δ be the roots of the equations x2+ax+b=0 and x2+bx+a=0∴α+β=-a,αβ=b,γ+δ=-b and γδ=aWe are givenα-β=γ-δ∴α-β2=γ-δ2α2+β2-2αβ=γ2+δ2-2γδ⇒α+β2-4αβ=(γ+δ)2-4γδ⇒-a2-4b=-b2-4a⇒a2-4b=b2-4a⇒a2-b2+4a-4b=0⇒a-ba+b+4=0⇒a+b+4=0 a-b=0 not possible because a≠b Regards 59 View Full Answer Ajitan answered this Anser is option A 3