If the discriminant of the equation 6x 2 - bx + 2= 0 is 1,then the value of 'b' is:
A 7 (B) -7 (C) ±7 (D) ±7
Dear student
The given quadratic equation is,
6x 2 - bx + 2 = 0
We have , A = 6 ; B = - b ; C = 2
Discriminant, D = B2 - 4AC = (- b)2 - 4(6) (2) = b2 - 48
But, D = 1
so, b2 - 48 = 1
⇒ b2 = 49
⇒ b = +7 or -7
Regards
The given quadratic equation is,
6x 2 - bx + 2 = 0
We have , A = 6 ; B = - b ; C = 2
Discriminant, D = B2 - 4AC = (- b)2 - 4(6) (2) = b2 - 48
But, D = 1
so, b2 - 48 = 1
Regards