IF THE ECCENTRICITY OF THE ELLIPSE X SQUARE /(A SQUARE + 1) + Y SQUARE / ( A SQUARE + 2 ) = 1 IS ( 1/ SQUARE ROOT OF 6 ) THEN LATUS RECTUM OF ELLIPSE IS ANSWER ----- 10 / ROOT 6

Dear Student,
Please find below the solution to the asked query:

x2a2+1+y2a2+2=1Given that e=16On comparing it withx2A2+y2B2=1 B>A, we get,A2=a2+1 and B2=a2+2e2=B2-A2B2162=a2+2-a2-1a2+216=1a2+2a2+2=6a2=4Length of latus ractum=2A2B=2a2+1a2+2=2.54+2Length of latus ractum=106 units

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