If the energy released by an electron jumped from the fourth orbit to the third orbit of hydrogen is 'x', then what would be the energy difference when it jumps from the third orbit to the second orbit ? Share with your friends Share 3 Shruti Srivastava answered this Dear Riya, E=hcλ where e=energy, h=planck constant, c=speed of light in vaccumλ=wavelength of light or emitted light1λ=1.09×1071n12-1n22 m-1; where n1=ground E level; n2=higher energy levelso E=1.09×107×hc 1n12-1n22 J1.09×107×hc the value is constant in both casewhen n1=3 & n2=4E=1.09×107×hc19-116=5.3×105×hc=xso when n1=2 & n2=3E=1.09×107×hc14-19=15.1×105×hc=2.85x (approx)then difference in energy will be (2.85-1)x=1.85 xRegards 1 View Full Answer