If the equation 8x 2 +8xy+2y2+38x+19y+35=0 represents a pair of staight lines,then what is the perpendicular distance between them?
In ans. it is given that:
Distance between the given lines=7-5/2 whole divided by underroot of 22+12
how? what is the formula used? please explain.

Dear Student,
Please find below the solution to the asked query:

If ax2 + 2hxy + by2 + 2gx + 2fy + c = 0 represents a pair of parallel straight lines,then the distance between them is given by,d=2g2-acaa+bThe given equation is,8x2 +8xy+2y2+38x+19y+35=0Here, g=19, a=8, b=2 and c=35.Hence the distance is,d=2192-8×358×8+2d=2361-2808×10d=2814×2×10d=8120d=925Hope this is the answer.

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