if the first term of an AP is 2 and common difference is 4 then find the sum of its first 40 terms.( experts please give the answers with same numbers which is provided in question don’t change the numbers and don’t provide any link.)​​

Let a be the first term and d be the common difference.Now, a = 2; d = 4Now, sum of first n terms of AP is given by,Sn = n22a + n-1dS40 = 4022×2+39×4=204 + 156=20 × 160=3200

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