If the mean of y and 1/y is M, then the mean of y3 and 1/y3 is : Share with your friends Share 0 Shipra Dang answered this Dear Student, Mean of y, 1y is M ⇒12y+1y=M .....i⇒123y+1y3=M3⇒18y3+1y3+3y2y+3yy2=M3⇒18y3+1y3+3y+3y=M3⇒18y3+1y3+3y+1y=M3⇒18y3+1y3+3M=M3 by i⇒18y3+1y3+38M=M3⇒18y3+1y3=M3-38M⇒12y3+1y3=4M3-38M⇒12y3+1y3=4M3-32M Thus, mean of y3, 1y3 is 4M3-32M. Regards, 0 View Full Answer Saiteja answered this Youre going to fiitjee admission test right? Even im not getting that sum 1
