# iF THE MID POINT OF THE LINE JOINING (3,4) AND (K,7) IS (X,Y) AND 2X + 2Y + 1 = 0 FIND THE VALUE OF K  .

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so we have the midpiont formula is

substitute the values in the places of x and y terms

we get (3+k/2 , 4+7/2)

===> x= 3+k/2 and y = 11

substitute thre value of x and y terms the equation 2x + 2y+1 = 0

we get 6+2k/2 +11+1 = 0

===> 6+2k/2 = -12  now cross multiply

===> we get  6+2k = -24

===> 2k = -24 -6

==> k = -30/ 2

k = -15

therefore the value of k = -15.....thumbs up pls

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