If the middle term of (1+x)^2n is the greatest term then X lies between A) n-1 and n B)n/(n+1) Share with your friends Share 4 Varun.Rawat answered this The exponent of 1+x in 1+x2n is an even number 2n.So, 2n2+1th i.e. n+1th term is the middle term in the binomial expansion of 1+x2n.Now, Tn+1 = Cn2n 12n-n . xn = Cn2n . xnNow, we are given that greatest term is Cn2n . xn.So, Cn-12n . xn-1 < Cn2n . xn and Cn+12n . xn+1 < Cn2n . xn⇒Cn-12nCn2n < x < Cn2nCn+12n⇒2n!n+1! . n-1! × n! . n!2n! < x < 2n!n! . n! × n+1! . n-1!2n!⇒nn+1 < x < n+1n 16 View Full Answer Mayank Deshpande answered this Options are B) n/(n+1) -6 Mayank Deshpande answered this Unable to send options -8