if the points A (-4,-2) B(3,-5) C(3,2) and D(2,a)form a parallelogram,find the value of "a" and the height of the parallelogram taking ABas base


Since opposite sides of a parallelogram are equal. Therefore,
AB=CDAB2=CD2           Using distance formula between two points; d=x2-x12+y2-y123+42+-5+22=2-32+a-2249+9=1+a-22a-22=57a-2=±57a=2±57
Area of  having coordinates x1,y1; x2,y2 ; x3,y3 is given by,area = 12x1y2-y3 + x2y3-y1 + x3y1 - y2Area of ||gm ABCD=2×Area of ΔABC                                    =2×124×-5+3×2+3×-2-3×-2+3×-5+4×2                                    =-20+6-6--6-15+8                                    =-20+13                                    =7 square unitNow,Area of ||gm ABCD=Height of ||gmh×Base ABHeight of ||gmh=Area of ||gm ABCDBase AB                               =73+42+-5+22                               =749+9                               =758 unit
Hence, Height of ||gmh is 758 unit.

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