If the points P(m,n),Q(-3,-1)and R(3,4) are such that PQ=PR,THEN (1) m=n (2)10n+12m=15 (3)5n+6m=7 (4)10n+12m=9 Share with your friends Share 1 Rishabh Mittal answered this PQ=-3-m2+-1-n2PR=3-m2+4-n2As PQ=PR-3-m2+-1-n2=3-m2+4-n2Squaring on both sides , we get-3-m2+-1-n2=3-m2+4-n29+m2+6m+1+n2+2n=9+m2-6m+16+n2-8n6m+2n+10=-6m-8n+2512m+10n=15Correct answer is 2. 10n+12m=15 1 View Full Answer