If the potential of the following electochemical cell is 1.29V at 29 degree C then x = __ Mg | Mg2+(xM) || Fe2+(0.01M) | Fe This question has not been answered yet! Don't worry! You can check out similar questions with solutions below ... Fe (2) Zn oxidises Fe2• (3) Zn reduces Mg2 ... following cells ... ... at 29 degree C then x = __ Mg | Mg2+(xM) || Fe2+(0.01M) | Fe
