If the radius of the circle touching (x-2)² + y² = 1 and the angle bisectors of the transverse common - Maths - Conic Sections

Question

If the radius of the circle touching (x-2)² + y² = 1 and
the angle bisectors of the transverse common tangents of (x +-
2)² + y² = 1 is p +- √q, then p+q is equal to
Answer is 9

Rashika · Answer

Answer
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If the radius of the circle touching (x-2)² + y² = 1 and the angle bisectors of the transverse common tangents of (x +- 2)² + y² = 1 is p +- √q, then p+q is equal to ... Answer is 9