If the solubility product Ksp of a sparingly soluble salt MX2 at 25°C is 1.0*10^-11 , the solubility of the salt in mole litre ^-1 at this temperature will be Share with your friends Share 3 Pratibha Pandey answered this Dear student, MX2→M++2X- s 2sas given Ksp=1.0×10-112ss=1.0×10-112s2=1.0×10-11s2=0.5×10-11s=0.5×10-11s=5×10-12s=2.23×10-6mol/litre Regards -12 View Full Answer
