If the solubility product Ksp of a sparingly soluble salt MX2 at 25°C is 1.0*10^-11 , the solubility of the salt in mole litre ^-1 at this temperature will be

Dear student,

MX2M++2X-              s       2sas given Ksp=1.0×10-112ss=1.0×10-112s2=1.0×10-11s2=0.5×10-11s=0.5×10-11s=5×10-12s=2.23×10-6mol/litre


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