If the standard electrode potential of Cu+2/Cu electrode is 0.34 V, what is the electrode potential at 0.01 M concentration of Cu+2 ?

Dear Student,

According to Nernst equation, Ecell=E°cell-0.0591nlog[Cu2+][Cu]since Cu is a solid, so [Cu]=1Ecell=0.34-0.05912log(0.01)        =0.34-0.05912(-2)        =0.399 V

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