If the straight line 3x+4y=k, touches the circle x2+y2=16x, then what is the value of k? Share with your friends Share 7 Nishima Pasricha answered this x2+y2=16x⇒x2-16x+y2=0⇒x2-16x+y2+64=64⇒x-82+y2=82Center of circle is (8, 0) and radius of the circle is 8 units. It is given that the line 3x+4y=k touches the circle, that means as circle is passing through the origin that means (0, 0) will satisfy the given equation.∴3×0+4×0=k⇒k=0 -30 View Full Answer
