If the sums of n terms of 2 A.P. are in ratio (3n+5)/(5n+7), then find their nth terms ratio

Let the first terms and the common differences of the given A.P.'s be a 1, a 2, and d 1, d 2

and 

 

their sum of n th terms be denoted by sn and sn'

 

Given:

 

Now, Nth term of A.P is given by, a+(N-1)d

Hence, the ratio of their Nth terms = (3N+1):(5N+11)

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 NTH TERM = Sn  - Sn-1

  • Sn/sn` = 3n+5
  •                5n +7
  •  
  • an =          [ 3n + 5 - 3(n-1) -5] =  [3n+53n +3 -5]      = 3
  •  an`           [5n +7 - 5(n-1) - 7]    [5n+- 5n +5 -7]       5

                                    PLS IGNORE BULLETS. they r just 4 easy representation of division                                                                                                                   

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