If the sums of n terms of 2 A.P. are in ratio (3n+5)/(5n+7), then find their nth terms ratio
Let the first terms and the common differences of the given A.P.'s be a 1, a 2, and d 1, d 2,
and
their sum of n th terms be denoted by sn and sn'
Given:
Now, Nth term of A.P is given by, a+(N-1)d
Hence, the ratio of their Nth terms = (3N+1):(5N+11)