If the value of a machine is rupees p and it depreciates at r% per annum then find its value after 2 years

Dear Student 

Given : Present Value = Rs. p
Rate of depreciation  = r%
Time (n) = 2 years
Value after 2 years will be  = $p{\left(1-\frac{r}{100}\right)}^n$

= $p{\left(1-\frac{r}{100}\right)}^2$ (Ans.)

Regards
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