If the vertices of a triangle are (3, -5), (-7, 4), (10, -k) and its centroid is (k, -1) then find the value of k.

Dear Student,
Centroid of a triangle=x1+x2+x33,y1+y2+y33
k,-1=3-7+103,-5+4-k3On comparing x and y we have,k=3-7+103 or -1=-5+4-k33k=10-4 or -3=-1-k3k=6k=63=2 or k=2So k=2
Regards
 

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