If three angles of a triangle are in the ratio 3:7:10 show that triangle is right angled
Let the angles be 3x, 7x and 10x.
By the Angle Sum Property of triangle,
3x+7x+10x = 180 (degrees)
=> 20x = 180
=> x = 180/20
=> x = 9
Now,
The first angle = 3x = 3(9)
= 27 degrees.
The second angle = 7x = 7(9)
= 63 degrees.
the third angle = 10x = 10(9)
= 90 degrees.
Therefore, the triangle includes a right angle, and two acute angles. Hence, it is a right triangle
H.P.
By the Angle Sum Property of triangle,
3x+7x+10x = 180 (degrees)
=> 20x = 180
=> x = 180/20
=> x = 9
Now,
The first angle = 3x = 3(9)
= 27 degrees.
The second angle = 7x = 7(9)
= 63 degrees.
the third angle = 10x = 10(9)
= 90 degrees.
Therefore, the triangle includes a right angle, and two acute angles. Hence, it is a right triangle
H.P.