If Tr denotes the rth term in the expansion of (1+x)n in ascending powers of x ( n being a natural number), prove that

r(r+1)Tr+2=(n-r+1)(n-r)x2Tr

given hint Tr=nCr-1x r-1 and Tr+2=nCr+1xr+1

Given, Tr be the rth tern in the expansion of 1+xn in ascending powers of x. So,Tr=Cr-1nxr-1And, Tr+2=Cr+1nxr+1Now, L.H.S.=rr+1Tr+2            =rr+1Cr+1nxr+1            =rr+1n!r+1!n-r-1!xr+1            =rr+1n!r+1rr-1!n-r-1!xr+1                 r+1!=r+1rr-1!            =n!r-1!n-r-1!xr+1Multiply and divid n-r+1n-r, we have,            = n-r+1n-r×n!r-1! n-r+1n-rn-r-1!xr+1            = n-r+1n-r×n!r-1! n-r+1!xr+1                               n-r+1!=n-r+1n-rn-r-1!            = n-r+1n-r×n!r-1! n-r+1!x2xr-1            =n-r+1n-rx2 n!r-1! n-r+1!xr-1            =n-r+1n-rx2×Cr-1nxr-1            =n-r+1n-r x2Tr            =R.H.S.Hence proved

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