If two vertices of an equilateral triangle are (1, -1) and (-root 3, -root 3), find the coordinates of the third vertex. Share with your friends Share 1 Zuhaib Ul Zamann answered this Dear student, Let A≡(1,-1) and B≡(-3,-3). let third vertex be C≡(x,y)Slope of AB=-3+1-3-1=2-3Hence AB is at angle of tan-1(2-3) =15∘ with x-axisHence slope of AC is tan(15+120)=-cot(45)=-1 or tan(15-120)=cot(15)mAC=-1 or 2+3Also when slope of AC is -1 slope of BC=tan(60+15)=2+3and when slope of AC is 2+3 slope of BC=tan(15-60)=-1Hence mBC=2+3 or -1Case ImAC=-1 mBC=2+3equation of ACy+1=-1(x-1)y=-x (I)equation of BC isy+3=(2+3)(x+3) IIsolving I and II we getx=-1 ,y=1i.e C≡(-1,1)Case IImAC=2+3 mBC=-1equation of AC=y+1=(2+3)(x-1) IIIequation of BCy+3=-1(x+3) IVsolving III and IV we getx=2-3,y=-2-3So C≡(2-3,-2-3)Regards 1 View Full Answer