If v is the volume of one molecule of a gas, then van der Waals constant 'b' is: (N₀= Avogadro's number)

a) $\frac{4 V}{N_{0}}$ b) 4V c) $\frac{N_{0}}{4 V}$ d) 4VN₀

Question

If v is the volume of one molecule of a gas, then van der Waals
constant 'b' is: (N0 = Avogadro's number)

a) 4   V N 0 b) 4V c) N 0 4 V d) 4VN0

Vartika Jain · Accepted Answer

Dear Student,

The vander waal constant b i e
 the excluded volume is given byb= 4×Volume of a single moleculeHere, Volume of one molecule = VTherefore, b = 4VHence, correct answer is b)

If v is the volume of one molecule of a gas, then van der Waals constant 'b' is: (N0 = Avogadro's number) a) 4 V N 0 b) 4V c) N 0 4 V d) 4VN0

If v is the volume of one molecule of a gas, then van der Waals constant 'b' is: (N₀= Avogadro's number)

a) $\frac{4 V}{N_{0}}$ b) 4V c) $\frac{N_{0}}{4 V}$ d) 4VN₀