If x^2 - 63x - 64 = 0 and p and n are integers such that p^n = x which of the following CANNOT be a value for p?
A) -8
B) -4
C) -1
D) 4
E) 64
Dear student
We shall find the roots of the given equation
x 2-63x-64=0
x 2-64x+x-64=0
x(x-64)+1(x-64)=0
(x-64)(x-1)=0
x= 64 and x=1 are the roots of the given equation
Now, x = 64 = 43
To express the value of x in the form of pn where p and n are both integers
option A: we can express it as (-8)2 = 64 = x
option B: we cannot express -4 in the form of pn to get 64 as 43 = 64
option C: we can express it as (-1)2 = 1 = x
We shall find the roots of the given equation
x 2-63x-64=0
x 2-64x+x-64=0
x(x-64)+1(x-64)=0
(x-64)(x-1)=0
x= 64 and x=1 are the roots of the given equation
Now, x = 64 = 43
To express the value of x in the form of pn where p and n are both integers
option A: we can express it as (-8)2 = 64 = x
option B: we cannot express -4 in the form of pn to get 64 as 43 = 64
option C: we can express it as (-1)2 = 1 = x
option D: we can express it as 641 = 64 = x
therefore correct option is B
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Regardstherefore correct option is B
Hope this information will clear your doubts about topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.