if x=3sinAcosB,y=3sinAsinB and Z=3cosA then find the value of xsqr+ysqr+zsqr Share with your friends Share 0 Varun.Rawat answered this We have,x = 3 sin A . cos By = 3 sin A . sin Bz = 3 cos ANow, x2 + y2 + z2=3 sin A . cos B2 + 3 sin A . sin B2 + 3 cos A2=9 sin2A . cos2B + 9 sin2A . sin2B + 9 cos2A=9 sin2Acos2B + sin2B + 9 cos2A=9 sin2A × 1 + 9 cos2A As, sin2θ + cos2θ = 1=9sin2A + cos2A=9×1=9 0 View Full Answer Jegannathan Anandaraman answered this Hi Mazz, given x = 3 sin A cos B ==> x^2 = 9 sin^2 A cos^2 B And y = 3 sin A sin B ===> y^2 = 9 sin^2 A sin^2 B So x^2 + y^2 = 9 sin^2 A ( cos^2 B + sin^2 B) = 9 sin^2 A Also z = 3 cos A ===> z^2 = 9 cos^2 A So x^2 + y^2 + z^2 = 9 sin^2 A + 9 cos^2 A = 9 (sin^2 A + cos^2 A) = 9 2