If x = a cos theta + b sin theta and y = a sin theta - b cos theta prove that x square + y square = a square + b square

Dear Student,

x = a cosθ + b sinθ  and y = a sinθ - b cosθ
L.H.S. = x2 + y2
= (a cosθ + b sinθ)2 + (a sinθ -b cosθ)2
= a2cos2θ + 2ab cosθ sinθ + b2sin2θ + a2sin2θ - 2absinθ cosθ + b2cos2θ
= (a2 + b2) cos2θ + (b2+a2) sin2θ 
= (a2 + b2)cos2θ + (a2+b2) sin2θ
= (a2 + b2)(cos2θ + sin2θ)
= (a2 + b2)                                      [∵ cos2θ + sin2θ = 1]
= R.H.S.

Hence Proved.


Regards

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