If x and y are two positive real numbers such that x^2+4y^2=17 and xy= 17, then find the value of (x+2y)

I already asked this question but it was not satisfactory. please answer it.

Question

If x and y are two positive real numbers such that x^2+4y^2=17 and
xy= 17, then find the value of (x+2y)

I already asked this question but it was not satisfactory please
answer it

Ajanta Trivedi · Accepted Answer

the given equations are:
x2+4y2=17 and xy=17x2+(2y)2+2*x*2y=17+4xyx+2y2=17+4*17(x+2y)2=17+68(x+2y)2=85x+2y=±85

hope this helps you