If x belongs to {1,2,3,...,9} and fn (x)=xxx....x(n digits) then fn^2+fn2 is This question has not been answered yet! Don't worry! You can check out similar questions with solutions below ... belongs to {1,2,3,...,9} and fn (x)=xxx....x(n digits) then ... ... belongs to {1,2,3,...,9} and fn (x)=xxx....x(n digits) then ... ... belongs to {1,2,3,...,9} and fn (x)=xxx....x(n digits) then ... ... x belongs to real then prove that f(x) is a periodic fn and ...
