if x-iy=underroot [(a-ib)/(c-id)]

prove that(x2+y2)2= a2+b2/c2+d2

just remember the comjugate of a complex number can be obtained by changing i to -i

then multiply the complex number with its conjugate

and  i2  = -1

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the answer is

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the answer is

plz....thumbs up..if u lyk it....
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there's a slight error in the second step :it'd be - "its conjugatex + iy = sqrt [ (a+ib) / (c+id) ]"the "/" symbol was not given in between! Thanks!

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Answer is in the image below. Olease upvote the answer Hare Krishna Thank You Very Much Siddhant Bhardwaj
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Ghochu , lol
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Yo-Yo honey singer
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If only u can understand Handwriting Simple answer Upvote

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Hi this is the easiest way to understand

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