if x=log t + sin t, y = e^t + cost t, find dy/dx

We have,x=logt+sint     .....1y=et+cost     .....2Differentiating 1 & 2 w.r.t. t, we getdxdt=1t+cost     .....3dydt=et-sint    .....4Now,dydx=dydt×1dxdt=et-sint×11t+cost               Using 3 and 4=tet-sint1+tcost

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