IF x+y=9 and xy=16,find the value of(x2+y2)

 x2+ y2 = (x+y)2 - 2xy

=92- 32=81-32=49

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 thumbs up plss

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So,

(x+y)2 =(9)2

x2+y2+2(xy) = 81

x2+y2+2(16)=81

x2+y2+32=81

x2+y2=81-32

x2+y2=49

 

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thnx both of u!

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I know this
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thank it help me in my studies
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It's very easy x square + y square will be 49
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ANSWER IS 49
 
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Dout
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Please find this answer

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Please find this answer

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 THIS IS YOUR ANSWER.
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What????
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Given, x+y=9 and xy=16.



We know, (a+b)2=a2+2ab+b2.

Then,
(x+y)²=x²+2xy+y²
⟹  (9)²=x²+2(16)+y²
⟹  81=x²+32+y²
⟹  x²+y²=81−32=49.
 
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