If x, y, z are in AP and x^2, y^2 and z^2 are in HP then prove that its possible when x, y, z are equal or when -x/2, y, z are in GP Share with your friends Share 1 Ishwarmani answered this Dear Student,Please find below the solution to the asked query:∵x,y,z are in AP∴ y = x + z2 ...(1)and x2,y2,z2 are in HP∴ y2 = 2x2z2x2+z2 ...(2)from (1) and (2),⇒x + z22 = 2x2z2x2+z2⇒x + z2x2+z2 = 8x2z2⇒x2+z2+2xzx2+z2 = 8x2z2⇒x2+z22+2xzx2+z2-8x2z2 = 0⇒x2+z22-4x2z2 +2xzx2+z2-4x2z2 = 0⇒x2-z22+2xzx2+z2-2xz = 0⇒x2-z22+2xzx-z2 = 0⇒x-z2x + z2 + 2xz = 0when x-z2 x = zand from 1,y = x + x2 = x∴x = y = zwhen x + z2 + 2xz = 0⇒x2+z2+4xz=0⇒x2+z2=-4xzand from 2,putting x2+z2 = 2x2z2y2⇒2x2z2 y2 =-4xz⇒xz = -2y2⇒y2 = -x2× z∴-x2,y,z are in GP.Hope this information will clear your doubts about the topic. If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible. -1 View Full Answer