if x,y,z are in GP then prove that:px+y x ypy+z y z = 00 px+y py+z Share with your friends Share 12 Anuradha Sharma answered this x, y, z are in GP so, y2=xz....1Now taking LHS, px+yxypy+zyz0px+ypy+zNow expanding along R1 we get, =px+ypy2+yz-pzx-yz-xp2y2+z2+2pyz+yp2xy+py2+pxz+yz=px+ypxz+yz-pzx-yz-xp2y2+z2+2pyz+yp2xy+pxz+pxz+yz using equation1=0-xp2y2-xz2-2pxyz+xp2y2+2pxyz+y2z=-xz2+xz2 using equation1=0 13 View Full Answer
