If y=A sin(wt-kx),then the value of dy/dx is. Please explain this question in detail.
Dear student
y = A sin(wt-kx)
Then, dy/dx = A cos(wt -kx) * d/dx(-kx)
dy/dx = -Ak cos(wt - kx)
So, D is correct option .
Hope this helps
Regard
y = A sin(wt-kx)
Then, dy/dx = A cos(wt -kx) * d/dx(-kx)
dy/dx = -Ak cos(wt - kx)
So, D is correct option .
Hope this helps
Regard