If y = ax ^ a ^ x ……. infinity , prove that dy/dx = y2 log y / x[ 1 – y ( log x ) ( log y ) ] Share with your friends Share 9 Varun.Rawat answered this We have, y = axaxax....∞⇒y = axy⇒log y = xy log aTaking logarithm both sides, we getloglog y = log xy + loglog aloglog y = y log x + loglog adifferentiating both sides with respect to x, we get1log y×1ydydx = y × 1x + log x ×dydx + 0⇒dydx1y log y - log x = yx⇒dydx1 - y log y . log xy log y = yx⇒dydx = y2log yx1 - y log y . log x 33 View Full Answer