if y=e^x + log x/sin 3x, find dy/dx Share with your friends Share 1 Anuradha Sharma answered this Given y = ex+log xsin3xSo dydx=ddx ex+ddxlog xsin3x= ex+sin3xddxlog x-log xddxsin3xsin3x2= ex+sin3xx-3log x.cos3xsin3x2=ex+sin3x -3xlog x . cos 3xxsin3x2 7 View Full Answer Sankar answered this Let y= u+vLet u=ex du/dx= ex.let v= logx/sin3xdv/dx= (sin3x - 3xlogx . cos3x)/ x. (sin3x)2Hence dy/dx= ex +(sin3x - 3xlogx . cos3x)/ x. (sin3x)2 0
