if y=e1/2log(1+tan 2x) then find dy/dx.

Given y = e12log1+tan2xNow applying chain rule we get, so dydx= e12log1+tan2xddx12log1+tan2x= 12e12log1+tan2x1log1+tan2xddx1+tan2x=e12log1+tan2x2log1+tan2x0+sec22xddx×2x =e12log1+tan2x×sec22xlog1+tan2x

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