if y=f(e-x)and f'(x)=ln x then dy/dx at x =ln2 is

given: y=f(e-x)
dydx=f'(e-x).ddx(e-x)=-e-xf'(e-x)=-e-x.lne-x=-e-x.(-x)=xe-xdydxat x=ln2=ln2*e-ln2=ln2*eln(1/2)=12*ln2

hope this helps you

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