If y3 + x3 -3axy = 0, PT d2y/dx2 = -2a3xy/(y2-ax)3

google it u would get that on google ebooks

  • 1
y3+x3=3axy
​diff both the sides,
3y2.y1 + 3x2=3ay+3ax.y1
y1(y- ax) = ay - 3x2
y1= (ay - 3x2)/(y2- ax)
again diff both the sides,
y2= [ (y2-ax). (ay1 - 6x) - (ay - 3x​2). (2y.y1 - a)]/ (y2-ax)2
Input the value of y1 and you will get your answer
  • 3
Plz provide full answer to me
  • -7
Please find this answer

  • -3
Isko hal karana hai

  • -3
Hal karana hai

  • 0
Take 3axy as 3a(xy)..then apply product rule

  • 2
If y3 + x3 -3axy = 0, PT d2y/dx2 = -2a3xy/(y2-ax)3
  • -4
14 number hal karna hai

  • 3
All answers are wrong.
  • -1
All answers are not cometed and also wrong
  • -1
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