# If z = 10 , find the value of z3 - 3( z - 10)

10*10*10-3(10-10) = 1000-0 = 1000

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10*3 - 3 ( 10 - 10 )

30-3(0)

27*0

0

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10*3 -3(10-10)

30-3(0)

30-0

30

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o

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10*3-3(10-10)

30-3*0

=0.hi i am only in 6th std but i am trying to answer this question. am i right

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z=10

z3-3

10*3-3

30-3

27 ans

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z=10

z*3-3(z-10)

10*3-3(10-10)

(30-3)*0

= 0

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=10*3-3(10-10)

=(30-3)*0

=0

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Z=10
So,Zx3=30
10-10=0
=>30-0
=>0
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10*10*10-3*0=1000-0=1000
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Z3 -3(z-10) ;Ans=1000
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30-3(10-10)
30-3*10--3*10
30-30-30
=0
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ANS=0

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30(thirty)
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If z = 10
Therefore = z3 - 3 ( z - 10 )
= z3 - 3 x z - 10
= 10 x 3 - 3 x 10 - 10
= 27 x ( 10 - 10 )
= 27 x 0
= 0
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z=10
z3-3 (z-10)
10?3-3(10-10)
30-3(0)
30-0
0
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Ans finally student30
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z=10
Then
=z3-3(z-10)

=10*3-3(10-10)

=30
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z3-3(z-10)
z=10
10*3-3(10-10)
30-3*0
30-0
=30
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• 0
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ans is 30

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z3-3(z-10)
10*3-3*10-10
260

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=10*3-3(10-10)
=30-3(10-10)
=27(10-10)
=270-270
=0
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zero
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Sorry
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• -1
The answer is z=10; 10*3=30; 30-3=27
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ans is 30
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980 is answer if z3 means z cube
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Hii
Equation- z3- 3(z-10)
Where z=10
Then,
10?3-3(10-10)
10?3-30+30
30-30+30
30-60
-30. Ans

Here we have first removed the bracket. As we know if before bracket there is minus sign then sign in the bracket changed.
Then we applied BODMAS rule.
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z3-3(z-10). (z=10) = 10 x 3 - 3(10- 10) =30 -3 x 0 =30 - 0 =30 So z3-3(z-10) is 30
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10?3-3(10-3)= 30-3(10-3)=27?7=154
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30

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30 is the correct answer ..
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= 10*3-3(10-10)
= 30-3*0
= 30
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=10*3-3(10-10)
=10*0
=0
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10?3-3(10-10)
30-3?0
27?0
0
• 0
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=10?3-3(10-10)
=30-30-30
=-30......
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If z = 10

= z3 - 3 ( z - 10 )
= z3 - 3 x z - 10
= 10 x 3 - 3 x 10 - 10
= 27 x ( 10 - 10 )
= 27 x 0?
= 0
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Hi, solve it yourself.

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the ans. is 1000
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Put z = 10 in z3 -  3(z - 10), we get
103 -  3(10 - 10) = 1000
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z3-3(z-10)
z=10
10*3-3(10-10)
30-3*0
30-0
=30
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GIVE
Z=10
=Z3-3(Z-10)
=10*3-3(10-10)
=30-3(10-10)
=27*0
=0
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Okay.
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I can solve this question
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Ans will be 0
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3*10-3<10-10>
30-3*0
30-0
0

take <>as a bracket
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What are you looking for?