if z=(3+7i)(p+iq),where p,q are non-zero integers,is purely imaginary then minimum value of |z|^2 is Share with your friends Share 3 Qazi Maaz Arshad answered this 3364 -18 View Full Answer Shloka answered this z=(3+7i) (p+iq)=(3p-7q)+i(3q+7p) now it is said z is purely imaginary so, 3p-7q=0 or p/q=7/3 or p/q + i = 7/3 +i (p+qi)/q=7+3i/3 from here the p+iq = 7+3i z= 58i |z^{2}|= 3364 4